(x-5)(2x^2+8x-7)=

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Solution for (x-5)(2x^2+8x-7)= equation: 


Simplifying
(x + -5)(2x2 + 8x + -7) = 0

Reorder the terms:
(-5 + x)(2x2 + 8x + -7) = 0

Reorder the terms:
(-5 + x)(-7 + 8x + 2x2) = 0

Multiply (-5 + x) * (-7 + 8x + 2x2)
(-5(-7 + 8x + 2x2) + x(-7 + 8x + 2x2)) = 0
((-7 * -5 + 8x * -5 + 2x2 * -5) + x(-7 + 8x + 2x2)) = 0
((35 + -40x + -10x2) + x(-7 + 8x + 2x2)) = 0
(35 + -40x + -10x2 + (-7 * x + 8x * x + 2x2 * x)) = 0
(35 + -40x + -10x2 + (-7x + 8x2 + 2x3)) = 0

Reorder the terms:
(35 + -40x + -7x + -10x2 + 8x2 + 2x3) = 0

Combine like terms: -40x + -7x = -47x
(35 + -47x + -10x2 + 8x2 + 2x3) = 0

Combine like terms: -10x2 + 8x2 = -2x2
(35 + -47x + -2x2 + 2x3) = 0

Solving
35 + -47x + -2x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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